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H3C GB0-382 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Routing Protocols | - Route redistribution concepts - BGP basics - OSPF advanced concepts |
| LAN Switching Technologies | - VLAN configuration and trunking - MAC address learning and forwarding - STP/RSTP/MSTP principles |
| Network Management and Troubleshooting | - Common network fault isolation methods - CLI-based diagnostics |
| Network Fundamentals | - Basic network device roles - TCP/IP model and OSI model - IPv4/IPv6 addressing and subnetting |
| IP Routing Technologies | - OSPF fundamentals and configuration - Route selection principles - Static routing |
| Network Security Basics | - ACL configuration and filtering - Basic device security hardening |
H3CSE-RS-RT Sample Questions:
1. 如果在 BGP 邻居建立成功后,使用 displabgp peer 命令所查看到的邻居状态为。
A) Connect
B) Active
C) Established
D) Full
2. 下列对于 Route-polic 的描述中,不正确的是 ______________?
A) 如果 Route-polic 中定义了一个以上的节点,各节点中至少应该有一个节点的匹配模式是 permit
B) 在 Route-polic 的同一个节点中,不同 if-match 子句之间的关系为与
C) 在 Route-polic 的一个节点中,必须至少包含一个 if-match 子句
D) 在一个 Route-polic 中,不同节点之间的关系为或
3. RTA 与 RTB , RTC , RTD 建立了 IBGP 对等体关系。 RTA 在向这三个 IBGP 对等体发布路由时候使用统一的过滤器 3001 ,通过 peer group 实现。
为实现如上目的,管理员在 RTA 上配置如下 :
[RTA-BGP] group in internal
[RTA-BGP] peer in connect-interface Loopback0
[RTA-BGP] peer 10.0.0.2 group in
[RTA-BGP] peer 10.0.0.3 group in
[RTA-BGP] peer 10.0.0.4 group in
[RTA-BGP] peer in filter-polic3001
则上述配置语句中,错误的是
A) [RTA-BGP] peer 10.0.0.2 group in [RTA-BGP] peer 10.0.0.3 group in [RTA-BGP] peer 10.0.0.4 group in
B) [RTA-BGP] peer in connect-interface Loopback0
C) [RTA-BGP] peer in filter-polic3001
D) [RTA-BGP] group in internal
4. 某路由器上的 PBR 配置如下。
Polic-based-route pbr_a permit node 10
If-match acl 3000
Apploutput-interface serial 2/0
Polic-based-route pbr_a dennode 20
If-match acl 3000
假设该策略已成功应用,该路由器上的匹配 Acl 3000 的数据流将如何转发 ?
A) 匹配 Acl 3000 的数据流将按被丢弃
B) 匹配 Acl 3000 的数据流将按照默认路由转发
C) 匹配 Acl 3000 的数据流将不按照普通路由转发
D) 匹配 Acl 3000 的数据流将不按照策略路由转发
5. 路由器的 IP 路由表中有一条由 21.22.23.0/22 ,要把它导入 BGP ,应该如下哪一条指令 ?
A) network 21.22.23.0 255.255.254.0
B) network 21.22.23.0 mask 255.255.254.0
C) network 21.22.20.0 255.255.252.0
D) network 21.22.20.0 mask 255.255.252.0
Solutions:
| Question # 1 Answer: C | Question # 2 Answer: C | Question # 3 Answer: C | Question # 4 Answer: C | Question # 5 Answer: C |


